2015年4月12日 星期日

Curve fitting demo in ABC FORTH

Curve fitting demo in ABC FORTH

Ching-Tang Tseng
2015/4/12 Hamilton, New Zealand

1. Abstract

    This article demonstrates it is quite simple to translate a typical traditional BASIC program into ABC FORTH system. Original program implemented out curve fitting by Lagrange interpolating polynomial method. A test program, according to the value of the exponential function to be the input data, could give out all the coefficients of a polynomial by the specified order.

2. Reference

A BASIC Program for Exact Curve Fitting
It is often required to find a polynomial to fit some function for which we know only a few values; the program given here in figure 1 calculates the coefficients of a polynomial such that the fit is exact for those data points.
If we have p+1 data points, then a polynomial of order p (or greater) can be found that will pass through all of these points (although in some special cases an exact polynomial of order less than p can be found). The minimum order polynomial is unique and it is the coefficients of this polynomial that are found by the program.
The program uses a method based on the Lagrange interpolating polynomial. For each value of abscissa: xj ( j is an integer: 0 j p ) we construct a polynomial: Aj (x) of order p that has the following properties: firstly, it has unity value at xj and secondly it is zero for all xi ( 0 i p; i j ). Aj (x) is constructed in two steps; firstly, using program statements: 130 - 190, a polynomial Fj (x) is constructed:
Fj (x) = ( x - x0 )( x - x1 ).......( x - xj-1 )( x - xj+1 )......( x - xp )
this clearly has the second property; by evaluating Fj (x) at xj (lines 220 - 230) we can find Aj (x) that has both properties (line 200):


Fj (x)
Aj (x)  
=  




Fj ( evaluated at xj )
Having calculated an Aj (x) for all xj , weighting the coefficients of each Aj (x) by the data value corresponding to xj  and summing the polynomials gives the required function; this is calculated and printed by statements 275 - 315.
The program given here assumes that the data are given for values of x = 0,1,2,3.... but appropriate scaling will allow fitting to any set of equally spaced data (modifications to statement 160 will allow nonuniformly spaced data to be fitted). Although written and tested on a Hewlett Packard 85 computer all of the statements should be suitable for other interpreters with little or (in most cases) no modification.
By way of example, a fifth order fit to the function exp(x) is calculated, for x = 0,1,2,3,4 and 5, giving the coefficients of the required polynomial:
H0 = 1
H1 = 2.74952
H2 = -3.30606
H3 = 3.03500
H4 = -.885002
H5 =.124822
The error (H0 + H1 x + H2 x2 + H3 x3 + H4 x4 + H5 x5 - exp(x)) is plotted in figure 2; as can be seen the fit is exact at x = 0,1,2,3,4 and 5 and elsewhere the interpolation is good.
Lawrence J. Mayes
Department of Electrical
Engineering Science
Essex University
Figure 1: Program Listing
100 COM A(57,56), C(57), H(56), Z(56)
105 INTEGER I, J, N, N1, P
110 CLEAR
115 LINPUT "Order of fit:",P$ @ P = VAL(P$) @ IF P > 56 THEN BEEP @ GOTO 115
120 GOSUB
245
125 FOR J = 0 TO P
130 GOSUB
235
135 C(0) = 1
140 FOR N = 0 TO P
145 N1 = N + 1
150 IF N = J THEN N = N + 1
155 IF N > P THEN 190
160 B0 = -N
165 FOR I = 1 TO N1
170 A(I,J) = B0 * C(I) + C(I-1)
175 NEXT I
180 A(0,J) = B0 * C(0)
185 FOR I = 0 TO N1 @ C(I) = A(I,J) @ NEXT I
190 NEXT N
195 GOSUB
220
200 FOR I = 0 TO P @ A(I,J) = A(I,J)/C(0) @ NEXT I
205 NEXT J
210 GOSUB
275
215 BEEP 100,190 @ DISP "finished" @ STOP
220
FOR I = P TO 1 STEP -1
225
C(I-1) = C(I) * J+C(I-1) @ NEXT I
230
RETURN
235
FOR I = 0 TO P + 1 @ C(I) = 0 @ NEXT I
240
RETURN
245
PRINT @ PRINT "INPUT DATA" @ PRINT "==========" @ PRINT
250
FOR I = 0 TO P
255
DISP @ DISP "Y value for abscissa value:"; I @ INPUT Z(I)
260
PRINT "Z("; I; ")= "; Z(I)
265
NEXT I
270
RETURN
275
PRINT @ PRINT "POLYNOMIAL FIT" @ PRINT "==============" @ PRINT
280
FOR I = 0 TO P @ H(I) = 0 @ NEXT I
285
FOR J = 0 TO P
290
FOR I = 0 TO P
295
H(I) = Z(J) * A(I,J) + H(I)
300
NEXT I
305
NEXT J
310
FOR I = 0 TO P @ PRINT "H("; I; ")= "; H(I) @ NEXT I
315
RETURN
320 END





NOTES
·         This article was published in ELECTRONIC ENGINEERING, 57, No 698; FEBRUARY 1985 p 38.
·         I have modified the programme to work with QBASIC - you can download a listing here.
Last updated: 1 Oct 2005;    © Lawrence Mayes, 1985/2000-2005


3. Program translated to the ABC FORTH system

\ ABC FORTH demo code: Lagrange interpolating polynomial curve fitting.
\ Author: Ching-Tang Tseng, Hamilton, New Zealand
\ Date2012-08-06(original), 2015-04-09(renewed for posting)
\ Contact: ilikeforth@gmail.com

\ Reference:
\ Lawrence J. Mayes ELECTRONIC ENGINEERING, 57, No 698; FEBRUARY 1985 p 38.
\ Description:
\ This program uses a method based on the Lagrange interpolating polynomial.
\ ZZ(i) is the input raw data array.
\ Matrix AAA(i,j) is the difference table manipulation matrix.
\ HH(i) is the output coefficients array of the fitted polynomial.

\ Remark: Original array and matrix structures in ABC FORTH system
\ without 0 indexes function. 0 index function to be included
\ after this program could be implemented out.

5 INTEGERS I J N N1 P

: INPUT-ORDER BASIC
10 PRINT " Order of fit: "
20 INPUTI P
30 IF P > 56 THEN 50
40 GOTO 70
50 PRINT " Order P cannot > 56, Re-enter please. "
60 GOTO -10
70 END ;

56 ARRAY ZZ

: SUB245 BASIC
10 RUN INPUT-ORDER
20 PRINT " Input data: "
30 PRINT " =========== "
40 FOR I = 0 TO P           \ Index start from 0
50 PRINT " Y value for X abscissa value: " ; I
60 INPUTR ZZ ( I )
70 PRINT " Y( " ; I ; " )=" ; { ZZ ( I ) }
80 NEXT I
90 END ;

57 ARRAY CC

: SUB235 BASIC
10 FOR I = 0 TO P + 1      \ Index is an arithmetical expression
20 LET { CC ( I ) = 0 }
30 NEXT I
40 END ;

56 ARRAY HH
57 56 MATRIX AAA

: SUB275 BASIC
10 PRINT " Polynomial fit: "
20 PRINT " =============== "
30 FOR I = 0 TO P
40 LET { HH ( I ) = 0 }
50 NEXT I
60 FOR J = 0 TO P
70 FOR I = 0 TO P
80 LET { HH ( I ) = ZZ ( J ) * AAA ( I J ) + HH ( I ) }
90 NEXT I
100 NEXT J
110 FOR I = 0 TO P
120 PRINT " HH( " ; I ; " )= " ; { HH ( I ) }
130 NEXT I
140 END ;

INTEGER I-1

: SUB220 BASIC
10 FOR I = P TO 1 STEP -1
20 LET I-1 = I - 1
30 LET { CC ( I-1 ) = CC ( I ) * I>R ( J ) + CC ( I-1 ) }
40 NEXT I
50 END ;

INTEGER Q
REAL B0

: MAIN BASIC
10 RUN SUB245
20 FOR J = 0 TO P
30 RUN SUB235
40 LET { CC ( 0 ) = 1 }
50 FOR N = 0 TO P
60 LET N1 = N + 1
70 IF N = J THEN 90
80 GOTO 100
90 LET N = N + 1
100 IF N > P THEN 200
105 LET Q = NEGATE N
110 LET { B0 = I>R ( Q ) }
120 FOR I = 1 TO N1
130 LET I-1 = I - 1
140 LET { AAA ( I J ) = B0 * CC ( I ) + CC ( I-1 ) }
150 NEXT I
160 LET { AAA ( 0 J ) = B0 * CC ( 0 ) }
170 FOR I = 0 TO N1
180 LET { CC ( I ) = AAA ( I J ) }
190 NEXT I
200 NEXT N
210 RUN SUB220
220 FOR I = 0 TO P
230 LET { AAA ( I J ) = AAA ( I J ) / CC ( 0 ) }
240 NEXT I
250 NEXT J
260 RUN SUB275
270 PRINT " Finished."
280 END ;

\ Usage
\ (1) Execute the following instruction GIVEN first to get the input data.
\ (2) Next, execute MAIN, then enter the data which you got above and
\     follows the Q & A procedures.

: GIVEN BASIC
10 RUN CR CR
20 FOR I = 0 TO 5
30 PRINT " Y( " ; I ; " )= " ; { EXP ( I>R ( I ) ) }
40 NEXT I
50 RUN CR CR
60 END ;

\S
Execution results:

GIVEN


Y( 0 )=        1.00000000000 
Y( 1 )=        2.71828182846 
Y( 2 )=        7.38905609893 
Y( 3 )=        20.0855369232 
Y( 4 )=        54.5981500331 
Y( 5 )=        148.413159103 

 ok
MAIN
Order of fit: ? 5
Input data:
===========
Y value for X abscissa value: 0 ? 1.00000000000
Y( 0 )=       1.00000000000 
Y value for X abscissa value: 1 ? 2.71828182846
Y( 1 )=       2.71828182846 
Y value for X abscissa value: 2 ? 7.38905609893
Y( 2 )=       7.38905609893 
Y value for X abscissa value: 3 ? 20.0855369232
Y( 3 )=       20.0855369232 
Y value for X abscissa value: 4 ? 54.5981500331
Y( 4 )=       54.5981500331 
Y value for X abscissa value: 5 ? 148.413159103
Y( 5 )=       148.413159103
Polynomial fit:
===============
HH( 0 )=        1.00000000000 
HH( 1 )=        2.74952933754 
HH( 2 )=       -3.30606647675 
HH( 3 )=        3.03499879102 
HH( 4 )=       -.885001709373 
HH( 5 )=        .124821886021 
Finished. ok

**************************************************

Original paper supplied output result data are:

H0 = 1
H1 = 2.74952
H2 = -3.30606
H3 = 3.03500
H4 = -.885002
H5 = .124822

**************************************************

4. This diagram shows the error condition in the specified range.



5. All implementation are finished in Win32Forth V6.14.03 added-in ABC FORTH V659 under W7 operating system.






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